Is it possible to use 'if-case' in place of a switch that has a coma delimited list as a case?

Question

Swift 2 introduced if-case which is supposed to be a more terse way of expressing a switch that only has a few cases. I'm wondering if there is a way of expressing a switch statement with a comma delimited list as an if-case.

let (a,b) = (1,0)

switch (a,b) {

case (1,0), (0,1), (1,1):
    print("true")
default:
    print("false")
}

What I've tried:

if case (a,b) = (1,0) {
    // works
}

if case (a,b) = (1,0), (0,1), (1,1) {
    // doesn't
}

This compiles but returns false for the (a,b) tuple:

if case (a,b) = (1,0),
case (a,b) = (0,1),
case (a,b) = (1,1) {
    print("if case true")
} else {
    print("if case false")
}

What I'd like to see:

I'd like to see an approach to shorten the above switch statement into a single if-case.

My Question

Is it possible to use if-case in place of a switch that has a coma delimited list as a case?

score 0 · Accepted Answer · answered Feb 11 '16 at 03:36

Well, after nearly a month. This is the closest I could get to satisfying the comma delimited list question. This actually satisfies the same requirement but in a different way.

let tuple = (1,0)

if case (0...1, 0...1) = tuple where !(a == 0 && b == 0) { return true }
else { return false }

Is it possible to use 'if-case' in place of a switch that has a coma delimited list as a case?

My Question

1 Answers1