I want to use the function gsub with sapply on a dataframe:
df_mod=as.data.frame(sapply(data_mod,gsub,pattern=data_mod$marq,replacement=""))
my problem is in the parameter pattern on the gsub function. In all the examples that I've seen, they pass a string to this parameter, like: pattern="string". For my case, I want to pass a variable as mentioned above : pattern=data_mod$marq
But I keep having these warnings that affected my results:
Warning messages:
1: In FUN(X[[i]], ...) :
argument 'pattern' has length > 1 and only the first element will be used
2: In FUN(X[[i]], ...) :
argument 'pattern' has length > 1 and only the first element will be used
3: In FUN(X[[i]], ...) :
argument 'pattern' has length > 1 and only the first element will be used
Is it possible to pass a variable to pattern parameter. If so, It will give me a perfect result.
Please help me.
UPDATE
switching sapply by mapply resolved the problem :
df_mod=as.data.frame(mapply(gsub,data_mod$marq,"",data_mod$nom_det))
