I am new to Ajax and have just started using PHP and I have made this working using PHP but it reloads the page, as one expects.
When I press a button it inserts a query according to which button is clicked. The php code is in the same file and no Ajax code is implemented as I couldn't figure out how.
These are the buttons which are in a form with no action and method POST,
<button type="submit" name="btnName" id="btnName" class="btn btn-success hidden-xs hidden-sm"></span>Name</button>
I have five of these, with different ids.
and this is the PHP code being used,
if(isset($_POST['btnName'])){
$sqlName = sprintf("INSERT INTO `PersonSong`(`Person_Id`, `Song_Id`) VALUES (1,%s)",mysql_real_escape_string($addressId));
$sqlNameQ = mysql_query($sqlName);
if($sqlNameQ){
echo "Added";
}else {
echo "You already know this!";
}
}
There are five of these also.
When this query is 'added' an icon at the bottom of the page is displayed if the person knows the song,
<?php
$sqlPersonSong = mysql_query("SELECT Person.Name AS PersonName, PersonSong.Person_Id AS PersonID, PersonSong.Song_Id AS SongID, Person.Facebook_Id AS FacebookID FROM PersonSong INNER JOIN Person ON PersonSong.Person_Id=Person.Person_Id WHERE PersonSong.Song_Id ='".$rows['SongId']."'"); ?>
<div class="hidden-xs hidden-sm">
<?php
$numRows = 1;
while($rowFacebookImg = mysql_fetch_array($sqlPersonSong)) { ?>
<a href="#">
<img class="circleImage img-circle" alt="Brand" src="http://graph.facebook.com/<?php print $rowFacebookImg['FacebookID'] ?>/picture?type=square&width=200&height=200"
data-toggle='tooltip' data-placement='top' title='<?php print $rowFacebookImg['PersonName'] ?>'>
</a>
<?php } ?>
</div>
</td>
How can update the image at the bottom without reloading the page? Thank you.