How to print a char a certain number of times?

Question

I am trying to create code that takes a user-inputted number, and store it as an int. I then print out 'int' number of lines, with 'int' number of 'char' in each of them. So say for example, the inputted number was 3, it would then output

XXX
XXX
XXX

However, when I try to do this, it just gives me the number it would calculate of the ASCII number * the inputted number. This is my current code:

public static void main(String[] args) {
    Scanner kb = new Scanner (System.in);
    System.out.println("Please enter a number:");
    int number = kb.nextInt();
    kb.close();
    char letter = 'X';
    int sqnumber = number * number;
    for (int i = 0; i < number; i++) {
            System.out.println (letter * number);
    }
}

However, this just gives me:

Please enter a number:
3
264
264
264

The line `System.out.println (letter * number);` prints 88 * 3, being 88 the ASCII value of X. What is the point of this line?: `int sqnumber = number * number;` — Orejano, Jan 21 '16 at 18:35
Checkout this post: http://stackoverflow.com/questions/2255500/can-i-multiply-strings-in-java-to-repeat-sequences The first answer may be helpful to you — Brian, Jan 21 '16 at 18:35

score 1 · Answer 1 · answered Dec 10 '19 at 16:29

1

There is repeat() method in String object(Appeared in Java 11). Example:

System.out.print("XXX\n".repeat(4));

answered Dec 10 '19 at 16:29

Иван Попов

36
3

score 0 · Answer 2 · answered Jan 21 '16 at 18:37

0

Nested loop:

for (int i = 0; i < number; i++) {
    for (int j = 0; j < number; j++) {
        System.out.print(letter + "");
    }
    System.out.println();
}

answered Jan 21 '16 at 18:37

Avalanche

386
2
10

score 0 · Answer 3 · answered Jan 21 '16 at 18:38

char is an integral type in Java. So you are multiplying ASCII value of 'X' with 3 each time. Edit your loop to -

    for (int i = 0; i < number; i++) {
        for (int j = 0; j < number; j++) {
            System.out.print(letter);
        }
        System.out.println();
    }

score 0 · Answer 4 · answered Jan 21 '16 at 18:47

0

For best performance, you probably want something like this:

private static void printSquare(int size) {
    char[] line = new char[size];
    Arrays.fill(line, 'X');
    for (int i = 0; i < size; i++)
        System.out.println(line);
}

answered Jan 21 '16 at 18:47

Andreas

154,647
11
152
247

score -1 · Accepted Answer · answered Jan 21 '16 at 18:41

-1

You need to have nested for loops and you are not using char Xcorrectly.

Try this

public static void main(String[] args) {
        Scanner kb = new Scanner(System.in);
        System.out.println("Please enter a number:");
        int number = kb.nextInt();
        kb.close();
        char letter = 'X';
        int sqnumber = number * number;
        for (int i = 0; i < number; i++) {
            for (int j = 0; j < number; j++) {
                System.out.print(letter);
            }
            System.out.println();
        }
    }

Output

Please enter a number:
4
XXXX
XXXX
XXXX
XXXX

answered Jan 21 '16 at 18:41

RockAndRoll

2,247
2
16
35

That doesn't seem to work for me. It prints out the Xs straight going down. – JoeMaynard Jan 21 '16 at 18:49
its a working example.You are messing something else. – RockAndRoll Jan 21 '16 at 18:50
You are welcome.I dont understand why down vote.Care to comment. – RockAndRoll Jan 21 '16 at 18:56

How to print a char a certain number of times?

5 Answers5