Java Help (Waituntil?)

Question

I want to create a java function, like a wait until this has passed in seconds, then they may preform the action.. Here is what I have:

    if(Minecraft.getMinecraft().gameSettings.keyBindJump.pressed)
        hasTimePassedS(2);
        Minecraft.getMinecraft().thePlayer.motionY = + 8;


    private boolean hasTimePassedS(int i) {
    long t0 = 0,t1 = 1;
     do{
     }
     while (t1-t0<1000);
    return false;

Note: These are two different samples, no correct { } format is used/regarded.

I want there to be a two second delay after the top code is activated before you can press it again.

Thanks!

For two seconds, so when they press it again before the delay, it does nothing — Hobo, Jan 22 '16 at 04:00

score 0 · Answer 1 · answered Jan 22 '16 at 04:10

0

You could create (and start) a Timer. Also, I'm pretty sure you meant += 8 (not = +8) Something like,

if (Minecraft.getMinecraft().gameSettings.keyBindJump.pressed) {
  Timer t = new Timer(2000, new ActionListener() {
    @Override
    public void actionPerformed(ActionEvent e) {
      Minecraft.getMinecraft().thePlayer.motionY += 8;
    }
  });
  t.start();
}

answered Jan 22 '16 at 04:10

Elliott Frisch

198,278
20
158
249

I mean = +, The timer does not exactly work, what imports would you import, just to make sure? – Hobo Jan 22 '16 at 04:18
@Hobo `javax.swing.Timer` (I linked to the Javadoc). Also, `+8` is just `8`. – Elliott Frisch Jan 22 '16 at 04:29
Still does not work, will get back with you tomorrow going to bed. – Hobo Jan 22 '16 at 04:32
What ends up happening is when the function is not pressed, it preforms the else function – Hobo Jan 22 '16 at 15:48
I have an else function after this, which makes the player float (- .04) in their y axis.. – Hobo Jan 22 '16 at 15:49
I will list the full source code when I get home, hopefully you can help – Hobo Jan 22 '16 at 15:50

Java Help (Waituntil?)

1 Answers1