How to extract numbers from textview android studio

Question

I have a textview in my app that contains numbers and letters and what I want to do is only get the numbers from it and apply a if statement. Something along the lines of;

    if (number == 1) {

        // do something

    } else if (number == 2) {

        // do something

    } else if (number >= 8) {

        // do something

    }

I have declared my textview like this;

TextView textview = (TextView) findViewById(R.id.number);

and the textview will contain texts similar to theses

textview.setText("1\nperson");
textview.setText("2\nperson");
textview.setText("3\nperson");
....
....
....

What I want to do is only get the text and then use the if statement shown below to carry out a task depending on the number. Any help would be nice.

Answer 1

You should split the string from the textview and convert numbers part to int and handle with try/catch if there's input error

TextView textview = (TextView) findViewById(R.id.number);
String text = textview.getText();
String[] parts = text.split("\\");
int number = Integer.parseInt(parts[0]);
if (number == 1) {
    // do something
} else if (number == 2) {
    // do something
} else if (number > 8) {
    // do something
}

+ You must use == not = It seems like you're new to java i think you should check java operators !

Answer 2

You can try this:

String text = textView1.getText().toString();

int number = Integer.parseInt(text.substring(0, 1));

if(number == 1){
    ....
} else if(number == 2){
    ....
}
....

Answer 3

You could extract a number from string by using a regex like this.

//This pattern will find all number groups in a string
Pattern p = Pattern.compile("(\\d+)"); 
Matcher m = p.matcher("3\nperson"); //The string you should get from your TextView
int number = 0;
if(m.find()) { //If a number in the string is found
    number = Integer.parseInt(m.group()); //Sets number to first found number group
}

Now you can use variable number in your if statement. I hope this helped you.

Answer 4

Since you are wanting to allow alphanumeric characters I would go with the following:

    String value = textView.getText().toString();
    value = value.trim().replaceAll("[^0-9]","|").replaceAll("(\\D)\\1+","$1");
    String values[] = value.trim().split("\\|");
    int intValues[] = new int[values.length];
    for(int i = 0; i < values.length; i ++){
        intValues[i] = Integer.parseInt(values[i]);
    }
    //assuming you only care about the first number
    int number = intValues[0];
    if(number == 1){
        //do something
    }else if(number == 2){
        //do something else
    }// etc.

The first line simply gets the raw text in your input. The second line has two parts to it, the first thing it does is substitute any non digit(0-9) characters sequences with a pipe "|". After this is done we go back and trim away any sequences of pipe with a single pipe.

Imaging this is your input: 1w22ee333rrr

After the first pass we leave it as: 1|22||333|||

After the second pass we leave it as 1|22|333|

We then split and store the values into a String array, loop over that array parsing all the numbers and storing them into an integer array. This will give you access to all the numbers being input, a little overkill but I had the time on my hands so I just gave you this as an option in case you find another application for it.