How can I achieve case condition in python?

Question

I am trying to achieve this using case statement

k=[]
for i in range(1,100):
     if i%3 and i%5 == 0:
            i=i,"divides with both"
     elif i%3 ==0:
            i =i,"divides with 3 "
     elif i%5 == 0:
            i = i,"divides with 5"
     else:
            i=i
     k.append(i)

Possible duplicate of [Replacements for switch statement in Python?](http://stackoverflow.com/questions/60208/replacements-for-switch-statement-in-python) — Kevin W., Jan 22 '16 at 17:35
I am trying to achieve similar functionality without using if condition — Harish, Jan 22 '16 at 17:48
This is the FizzBuzz problem (Google it), was this assigned to you as homework in a computer course? — cdlane, Jan 22 '16 at 18:48

cdlane · Accepted Answer · 2016-01-27T05:03:03.627

My initial response (as a comment above) is that this looks like a homework problem and shouldn't be on StackOverflow.

My second response is that you shouldn't be trying to emulate this style switch statement in Python as it embeds data in the code which is poor programming.

My third response is that achieving this functionality without any 'if' at all in the code is actually a tricky problem. So here's my wacky solution:

CASES = ("divides with both", False, False, "divides with 3", False, "divides with 5", "divides with 3", False, False, "divides with 3", "divides with 5", False, "divides with 3", False, False)

LIMIT = 100

k = []

for n in range (1, LIMIT + 1):
    result = ((n, CASES[n % len(CASES)]), n)

    k.append(result[result[0][1] == False])

print(k)

How can I achieve case condition in python?

1 Answers1