Python 3.x short version of code

Question

Is there a way shorter way to check for characters in a string? Thanks :D

check = input("Put in the letter: ")
word = "word"

if(check == word[0]):
    print(check)
if(check == word[1]):
    print(check)
if(check == word[2]):
    print(check)
if(check == word[3]):
    print(check)

score 5 · Answer 1 · answered Jan 22 '16 at 23:42

5

How about this:

if check in word:
    print(check)

answered Jan 22 '16 at 23:42

Leistungsabfall

6,368
7
33
41

2

It's not exactly the same, e.g. if `word = 'HELLO'` and `check = 'L'` – Peter Wood Jan 22 '16 at 23:53

score 4 · Answer 2 · answered Jan 22 '16 at 23:42

4

Something like

for l in word:
      if l == check:
            print (check)

Maybe ?

answered Jan 22 '16 at 23:42

Work of Artiz

1,085
7
16

Quick note: the code of @leistungsabfall will print the character once eventhough it might occur multiple times, whereas my code like your original code prints n times if the letter occurs multiple times in the word. – Work of Artiz Jan 22 '16 at 23:45

Python 3.x short version of code

2 Answers2