Using Json returned by PHP in AJAX

Question

My PHP script is returning a JSON object that I am receiving in AJAX call.

$arr[0] = $resp;
            $arr[1] = $e;
            return json_encode($arr);

Now in my AJAX call , I try to get the value but all I get is "/" or "'" .

I am doing this in AJAX.

dd = JSON.stringify(x.responseText); //this is the response from PHP which is correct I have verified.
alert(dd[0]); //supposed to output $arr[0] but it doesn't

Am I doing something wrong here?

I have seen this on SO

@u_mulder the problem is not about alert or console.log or printing, its about getting correct data. — PHP Tester, Jan 23 '16 at 13:18
Console.log and see what you have in dd. `JSON.stringify` btw makes json string from it's argument. Maybe you need `JSON.parse`? — u_mulder, Jan 23 '16 at 13:18

score 0 · Accepted Answer · answered Jan 23 '16 at 13:31

I think the JSON.parse solve your problem.

The JSON.parse() method parses a string as JSON, optionally transforming the value produced by parsing.

Examples

JSON.parse('{}');              // {}
JSON.parse('true');            // true
JSON.parse('"foo"');           // "foo"
JSON.parse('[1, 5, "false"]'); // [1, 5, "false"]
JSON.parse('null');            // null

Using the reviver parameter

JSON.parse('{"p": 5}', function(k, v) {
  if (k === '') { return v; } // if topmost value, return it,
  return v * 2;               // else return v * 2.
});                           // { p: 10 }

JSON.parse('{"1": 1, "2": 2, "3": {"4": 4, "5": {"6": 6}}}', function(k, v) {
  console.log(k); // log the current property name, the last is "".
  return v;       // return the unchanged property value.
});

Ref:

JSON.parse()

JSON Example - Object From String

Using Json returned by PHP in AJAX

1 Answers1