Notice: Undefined index: appointDate

Asked Jan 26 '16 at 13:42

Active Jan 26 '16 at 14:19

Viewed 11 times

Getting Undefined index error on appointDate when running the code shown below:

$searchData = mysqli_query($connectme, "SELECT * FROM registration WHERE caseNo = '".$caseNo."'");
$row = mysqli_fetch_array($searchData);
//Fix date for entry to form to day,month,year for display purposes only
$dateFixYear = substr($row['appointDate'], 0,4);
$dateFixMonth = substr($row['appointDate'], 5,2);
$dateFixDay = substr($row['appointDate'], 8,2);
$dateFixed = $dateFixDay . "/" . $dateFixMonth . "/" . $dateFixYear;
$row['appointDate'] = $dateFixed;

I would like to find the error in the code rather than ignoring it using -

error_reporting(E_ERROR | E_PARSE);

Thanks in advance.

edited Jan 26 '16 at 14:19

M. Schena

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asked Jan 26 '16 at 13:42

Andy Brockie

`appointDate` and `appointdate` in a loop, are two different animals and it may be a letter-case issue. – Funk Forty Niner Jan 26 '16 at 13:43
Please show the structure of the registration table. Its likely it does not have a row called appointDate – theINtoy Jan 26 '16 at 13:44

Notice: Undefined index: appointDate

0 Answers0