I have one python file (abc.py) which include several commands like make directory, copy commands. I want to execute it such like that,whenever I hit command for example abc --makedir on console, it should make directory. makedir is function which is written in abc.py.
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I had tried adding it in a path variable but it does not works. – Yagya Jan 27 '16 at 09:29
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Where is your code and what's the problem? – luoluo Jan 27 '16 at 09:31
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This sounds like you should use the shell, not Python. – tripleee Jan 27 '16 at 09:36
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The file name, including any extension, is how you invoke a script. If you want the command to be named `abc` then the file should be named `abc`. There is no requirement to have a `.py` extension on a Python script in Unix; in fact, for anything you want to use as a direct command, it's probably not a good idea. Just make sure you give the file a proper shebang line like `#!/usr/bin/env python` on the very first line of the file, and make sure the file is executable, and that the directory it's in is on your `PATH`. – tripleee Jan 27 '16 at 09:38
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there is a python file named abc.py and containing a function name makedir() which when called makes a new directory. i want to execute as abc --makedir it should make a new directory. – Yagya Jan 27 '16 at 09:43
1 Answers
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Rename abc.py to abc.
Make it executable:
chmod +x abc
Then add this at the first line of your script:
#!/usr/bin/python
From command line (if abc is in python path):
#abc
To create a directory like you said , you should parse arguments passed to python script.
For example:
import sys
if len(sys.argv)>1:
if sys.argv[1] == '--makedir':
makedir()
For more informations Look at this link What's the best way to grab/parse command line arguments passed to a Python script?
