JavaFX Coloring TableCell

Question

I need your help!

I've got a Table with rows in it (Name, etc..) Now, I want to color a specific tableCells background when the Object, laying on this row has got a specific value. But i only get it to read the value of this cell. But i need to read the Object (in my code called TableListObject) to know in wich color i need to color the cell. But this "color value" is not visible (has no column) in that row.

Here is my code:

for(TableColumn tc:tView.getColumns()) {
    if(tc.getId().equals("text")) {
        tc.setCellValueFactory(newPropertyValueFactory<TableListObject,String>("text"));
        // here i need to check the Objects value and coloring that cell
    }
}

Here is a HTML Fiddle to visualize my problem: https://jsfiddle.net/02ho4p6e/

Related, but slightly different: [Background with 2 colors in JavaFX?](http://stackoverflow.com/questions/16200901/background-with-2-colors-in-javafx) — jewelsea, Jan 28 '16 at 10:29

Iulian Gheorghita · Accepted Answer · 2016-01-28T10:31:00.477

Call the cell factory for the column you want and override the updateItem method. You need to check if it is empty and then if it is not you can do your object check and then you can set the color of the cell background or any other style you want. Hope this helps.

    tc.setCellFactory(column -> {
        return new TableCell<TableListObject, String>() {
            protected void updateItem(String item, boolean empty) {
                super.updateItem(item, empty);

                if (item == null || empty) {
                    setText(null);
                    setStyle("");
                } else {
                    if (item.equals("Something")) {
                        setStyle("-fx-background-color: blue");
                    } else {
                        setStyle("");
                    }
                }
            }
        };
    });

EDIT 1:

If you want to use the value of another cell in the same row. You will have to use the index of the row and get the items need for the check.

tc.setCellFactory(column - > {
   return new TableCell < TableListObject, String > () {
     protected void updateItem(String item, boolean empty) {
       super.updateItem(item, empty);

       if (item == null || empty) {
         setText(null);
         setStyle("");
       } else {
         int rowIndex = getTableRow().getIndex();
         String valueInSecondaryCell = getTableView().getItems().get(rowIndex).getMethod();
         if (valueInSecondaryCell.equals("Something Else")) {
           setStyle("-fx-background-color: yellow"); //Set the style in the first cell based on the value of the second cell
         } else {
           setStyle("");
         }

       }
     }
   };
 });

EDIT 2:

Improved answer based on suggestion. This uses the referenced object.

   else {
         TableListObject listObject = (TableListObject) getTableRow().getItem();
         if (listObject.getMethod().equals("Something Else")) {
           setStyle("-fx-background-color: yellow"); //Set the style in the first cell based on the value of the second cell
         } else {
           setStyle("");
         }
       }

Thank you. I had this already, but the problem is: The Value i need to check is not in "item" String. Because "item" String is only the Value of the current Cell. But my Value i need to check is in the **RowObject (and in no Cell)** — Mr. 0x50, Jan 28 '16 at 09:44
Well if the item is not a String you can change it to any type. Like Date etc. — Iulian Gheorghita, Jan 28 '16 at 09:56
Sure, but the Problem is, the Value i need to check is in that row, but not in that cell i want to color. — Mr. 0x50, Jan 28 '16 at 09:57
`getTableRow().getItem()` may be simpler, e.g., [Javafx, get the object referenced by a TableCell](http://stackoverflow.com/questions/13585164/javafx-get-the-object-referenced-by-a-tablecell) — jewelsea, Jan 28 '16 at 10:24

JavaFX Coloring TableCell

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