Shell Scripting; if statement outputting unexpected operator?

Question

I'm trying to write a shell script to delete 0kb files but the if statement keeps giving me errors, and i'm wondering if you can help me out

I have:

#!/bin/sh
EMPTY_FILE=$(find ${1-.} -size 0)
echo $EMPTY_FILE
echo "delete"
read text
if [ "$text" == "yes" ]; then echo yes; fi

error is

./deleteEmpty.sh: 6: [: yes: unexpected operator

Any help on whats wrong is useful! Thanks

This appears to work for me. That is, if I run that script, and type "yes", I get "yes" back. Is that not what you are expecting? — aghast, Jan 28 '16 at 16:42
Hm.. it doesn't work for me. is there something i need to install/change for this to work? Edit: oh man, i used /sh instead of bash — user2874977, Jan 28 '16 at 16:45
You are the `test` command in which you should use `=` for string comparison instead of `==`. If you are using bash, then `==` would be fine too. — P.P, Jan 28 '16 at 16:46
If you do switch your shebang to bash, use `read -p "delete? " text` -- and pick a better variable name. — glenn jackman, Jan 28 '16 at 16:55

score 3 · Answer 1 · edited May 23 '17 at 12:04

3

In plain sh the equality operator is =. == is a bashism. Either change your shebang line to #!/bin/bash, or change the test to:

if [ "$text" = "yes" ]; then echo yes; fi

#!/bin/bash

if [[ $text == yes ]]; then echo yes; fi

edited May 23 '17 at 12:04

Community

answered Jan 28 '16 at 16:46

John Kugelman

score 0 · Answer 2 · answered Jan 28 '16 at 16:41

0

Try to use double brackets:

if [[ "$text" == "yes" ]]; then echo yes; fi

answered Jan 28 '16 at 16:41

ForceBru

score 0 · Answer 3 · answered Jan 28 '16 at 16:43

0

I suppose you want to use bash. In that case the first line of your script should be

#!/bin/bash

answered Jan 28 '16 at 16:43

gollum

3 Answers3