PHP booleans var error

Question

I wrote a login script, but it doesn't work: In this script I can't log in

if($_SESSION['logged'] == TRUE){
echo "logged in";
}

if($_POST['pass'] == "blabla"){
$_SESSION['logged'] = TRUE;
}

if($_GET['logout']){
$_SESSION['logged'] = FALSE;
}

You have several... undefined variables... I don't get it. What do you not understand? — Sverri M. Olsen, Jan 28 '16 at 18:24
`===` and `==` are comparison operators and `=` is assignment operator. [http://php.net/manual/en/language.operators.php](http://php.net/manual/en/language.operators.php) — Rajdeep Paul, Jan 28 '16 at 18:25
`=` is assignment, `==` is loose typed comparison, and `===` is strict typed comparison. Reading the [docs](http://php.net/manual/en/language.operators.comparison.php) is a good start. — Dave Chen, Jan 28 '16 at 18:26

score 2 · Answer 1 · answered Jan 28 '16 at 18:22

2

Your first two lines are a comparison:

$var1 === TRUE;
$var2 == TRUE;

You want them to be a declaration

$var1 = TRUE;
$var2 = TRUE;

answered Jan 28 '16 at 18:22

score 0 · Answer 2 · answered Jan 28 '16 at 18:22

This is not legal syntax for setting a variable

var1 === TRUE;

And nor is this

var2 == TRUE;

Use = to set a variable to a value.

The === and == are comparison tests not value assignments.

This is also not going to do a test

if($var1 = TRUE){echo "3";}

it will set $var1 to be true, ditto the other 2 times you try this line for $var2 and $var3

PHP booleans var error

2 Answers2