php jquery dynamic dropdown

Question

I am having problem sending/reading ajax variable.

Ajax code is as below:

$.ajax({
    url: "/wp-content/themes/canvas-child/get-clients-dropdown.php?it=1",
    success: function(data) {
        $("#ClientID").html(data);
    }
});

I have tried to read it in another php file like this:

$InvoiceType = $_REQUEST['it'];
//$InvoiceType = $_POST['it'];
//$InvoiceType = $_GET['it'];

But none of above works. The variable $InvoiceType always stays empty.

What is the problem?

So `print_r` `$_REQUEST` in this another php file. And also print `$_GET` — u_mulder, Jan 29 '16 at 11:39
are u echo $InvoiceType; in php file , if not than it will not return 1 — devpro, Jan 29 '16 at 11:43
did u checked as @u_mulder said??? print_r($_REQUEST)... r u not getting values in php or in ajax response? — devpro, Jan 29 '16 at 12:02
This reminds me of a similar yet problem I had: https://stackoverflow.com/questions/33128993/how-to-send-a-post-request-using-httpie — k0pernikus, Jan 29 '16 at 12:48

score 0 · Answer 1 · edited Jan 29 '16 at 11:49

0

$.ajax({
      type: "GET",
      data: {it: "1"}, 
      url: "/wp-content/themes/canvas-child/get-clients-dropdown.php?it=1",
      success: function(data) {
         $("#ClientID").html(data);
      }
});

try this

edited Jan 29 '16 at 11:49

devpro

16,184
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answered Jan 29 '16 at 11:45

Rockers Technology

477
4
12

score 0 · Accepted Answer · answered Jan 29 '16 at 11:45

0

The best way is to use POST method like this : $.ajax({ method: "POST", url: ""/wp-content/themes/canvas-child/get-clients-dropdown.php", data: { it: 1, param2: "value2" } })

You can get your value in $_POST['it']

answered Jan 29 '16 at 11:45

Fabien

548
7
18

I have tried post method before, but wasn't working. – gdolenc Jan 29 '16 at 11:57
The method POST is not the only important line. 'data' line is necessary to send data to $_POST – Fabien Jan 29 '16 at 13:53

score 0 · Answer 3 · answered Jan 29 '16 at 11:46

0

Please try it with full url of file with get_template_directory_uri().

$.ajax({
    type: 'GET',
    url: '<?php echo get_template_directory_uri(); ?>/get-clients-dropdown.php',
    data: {it: 1},
    success: function(data) {
            $("#ClientID").html(data);
          }
     });

answered Jan 29 '16 at 11:46

Jalpa

697
3
13

File is executed, so this is not a problem. Like said, everything Works for me, exept I have problem transfering variable value. – gdolenc Jan 29 '16 at 11:56
@gdolenc Did you try it with send data from "data: {it: 1}," ? – Jalpa Jan 29 '16 at 11:59
@gdolenc Can you please check it with print_r($_REQUEST) on that file. – Jalpa Jan 30 '16 at 05:21

score 0 · Answer 4 · answered Jan 29 '16 at 13:08

0

You have to use it like this:

$.ajax({
    type: "POST",
    url: "/wp-content/themes/canvas-child/get-clients-dropdown.php?it=1",
    success: function(data) {
        $("#ClientID").html(data);
    }
});

Then in PHP File use this:

$InvoiceType = $_POST['it'];

answered Jan 29 '16 at 13:08

Atif Tariq

2,650
27
34

Are you using it in "get-clients-dropdown.php" file? – Atif Tariq Jan 29 '16 at 16:57
This is the beginning of my get-clients-dropdown.php file: '; – gdolenc Jan 29 '16 at 17:06
@gdolenc Welcome. Appriciated for your up vote. Thanks – Atif Tariq Jan 29 '16 at 18:37

php jquery dynamic dropdown

4 Answers4