Split String 2 times but with different splits ";" and "."

Question

Original String: "12312123;www.qwerty.com"

With this Model.getList().get(0).split(";")[1]

I get: "www.qwerty.com"

I tried doing this: Model.getList().get(0).split(";")[1].split(".")[1]

But it didnt work I get exception. How can I solve this?

I want only "qwerty"

You'd need to escape the `.`, i.e. `"\\."`. Period is a special character in regular expressions, meaning "any character". — Andy Turner, Feb 01 '16 at 17:59
http://stackoverflow.com/questions/14833008/java-string-split-with-dot — Reimeus, Feb 01 '16 at 17:59

Abdelhak · Answer 1 · 2016-02-01T18:04:53.647

1

Try to use split(";|\\.") like this:

 for (String string : "12312123;www.qwerty.com".split(";|\\.")) {

        System.out.println(string);
    }

Output:

  12312123
  www
  qwerty
  com

edited Feb 01 '16 at 18:04

answered Feb 01 '16 at 17:59

Abdelhak

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score 1 · Answer 2 · answered Feb 01 '16 at 18:03

1

Try this, to achieve "qwerty":

Model.getList().get(0).split(";")[1].split("\\.")[1]

You need escape dot symbol

answered Feb 01 '16 at 18:03

Mirjalol Bahodirov

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score 0 · Answer 3 · answered Feb 01 '16 at 18:02

0

You can split a string which has multiple delimiters. Example below:

String abc = "11;xyz.test.com";
String[] tokens = abc.split(";|\\.");
System.out.println(tokens[tokens.length-2]);

answered Feb 01 '16 at 18:02

Rupesh

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score 0 · Answer 4 · answered Feb 01 '16 at 18:02

0

The array index 1 part doesn't make sense here. It will throw an ArrayIndexOutOfBounds Exception or something of the sort.

This is because splitting based on "." doesn't work the way you want it to. You would need to escape the period by putting "\." instead. You will find here that "." means something completely different.

answered Feb 01 '16 at 18:02

Debosmit Ray

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@IdontwearString Most of the answers here will work for your case. Please mark whichever one explains this best, so that people can get to the correct answer sooner, in the future. – Debosmit Ray Feb 01 '16 at 18:12

Andy Turner · Answer 5 · 2016-02-01T18:09:13.990

You'd need to escape the ., i.e. "\\.". Period is a special character in regular expressions, meaning "any character".

What your current split means is "split on any character"; this means that it splits the string into a number of empty strings, since there is nothing between consecutive occurrences of " any character".

There is a subtle gotcha in the behaviour of the String.split method, which is that it discards trailing empty strings from the token array (unless you pass a negative number as the second parameter).

Since your entire token array consists of empty strings, all of these are discarded, so the result of the split is a zero-length array - hence the exception when you try to access one of its element.

score 0 · Answer 6 · answered Feb 01 '16 at 18:20

Don't use split, use a regular expression (directly). It's safer, and faster.

String input = "12312123;www.qwerty.com";
String regex = "([^.;]+)\\.[^.;]+$";
Matcher m = Pattern.compile(regex).matcher(input);
if (m.find()) {
    System.out.println(m.group(1)); // prints: qwerty
}

Split String 2 times but with different splits ";" and "."

6 Answers6