Slice string by character and not index

Question

I want to create variable from a long string to a small string.

e.g abcde!mdamdskm to abcde.

I know only what is the special character and not the index.

score 17 · Answer 1 · answered Jul 26 '17 at 02:28

17

For getting only first word use index after splitting.

a="abcde!mdamdskm"
print a.split("!")[0]

answered Jul 26 '17 at 02:28

Rohit-Pandey

`split()`, not `slice()`! Thank you! btw fyi `partition()` will keep separator in the results – Denis Jan 28 '22 at 10:39

score 7 · Answer 2 · answered Feb 02 '16 at 20:13

7

>>> "abcde!mdamdskm".split("!")
['abcde', 'mdamdskm']

This might not work if you have multiple instances of the special character:

>>> "abcde!mdam!dskm".split("!")
['abcde', 'mdam', 'dskm']

But you could fix that like this:

>>> "abcde!mdam!dskm".split("!", 1)
['abcde', 'mdam!dskm']

answered Feb 02 '16 at 20:13

inspectorG4dget

1

and how can I get only the first index to a variable? – ariel Feb 02 '16 at 20:14
1

@ariel: `mylist[0]` gives the first element in `mylist` – inspectorG4dget Feb 02 '16 at 20:14

2 Answers2