why different result for these strings?

Question

I found that this, but I don't know what the point.

String s1 = new String("heyheyhey");
String s2="heyheyhey";
String s3="heyheyhey";
if(s1==s2)System.out.println("s1 == s2");
if(s2==s3)System.out.println("s2 == s3");

Why different results for both if statements?

score 0 · Answer 1 · answered Feb 03 '16 at 06:53

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String class: 1.when use new keyword means get a new memory site. 2.when use "" style means will try to get the workds from constant pool,if doesn't exist it will return new memory site.

answered Feb 03 '16 at 06:53

Risk4U

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score 0 · Accepted Answer · edited May 23 '17 at 12:07

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== checks for the reference. .equals checks for the actual component.

In your case s1 and s2 are pointing to two different objects and s2 and s3 are sharing the common reference since there component is same.

Check out this question for detailed explanation.

edited May 23 '17 at 12:07

Community

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1

answered Feb 03 '16 at 06:55

Abdullah Khan

12,010
6
65
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@Artur - please rate this answer up if its accepted. – Abdullah Khan Mar 09 '16 at 06:19

why different result for these strings?

2 Answers2