How do I return a double without getting rounded:
int function() {
double d = 5.894;
printf("d=%f\n", d);
return d;
}
int main() {
double d = function();
printf("d=%f\n", d);
return 0;
}
This gives me
d=5.894000
d=5.000000
What am I missing here?
Your function returns ٰint it must return double
Change
int function()
to
double function()
iharob's answer is of course correct, but I think that it is also important to know how to avoid this kind of errors in the future.
I have also have not found any explicit reference of this behavior (implicit cast from a "large" numeric type to a "smaller" one), so I have asked a question about this.
Shortly put, by providing the correct compilation warning flags, these errors can be spotted at compile time (e.g. -Wconversion), as it's almost always a bug.
However, this behavior is by design, and as mentioned by Chris in a comment, sometimes it might be useful in terms of performance.
