Usage of increment operators

Question

#include <stdio.h>
#include <string.h>

int main()
{
int i=3,y;
y=++i*++i*++i;
    printf("%d",y);
}

The i value is initially getting incremented to 4.Then it is incremented to 5. therefore it is incremented to 6. accordingly result should come 216. but 150 is coming as a result.

It is really should be `216`.... So, perhaps, problem not in the code. Try rebuild the binary file, ro try different compiler (e.g. g++ insted of gcc) — VolAnd, Feb 04 '16 at 05:05
There are quite a few post on SO about sequence points and undefined behavior. Look them up. — R Sahu, Feb 04 '16 at 05:18

score 0 · Accepted Answer · answered Feb 04 '16 at 05:17

It will execute like this;

First it is considers like this,

y = (++i * ++i) * ++i // so first i is incremented to 4 and again it will incremented to 5.

So now first expression will executed like this
```
y = (5 * 5) * ++i; 
y = 25 * ++i;
```
Now again i is incremented to 6 and final expression is like this,
```
y = 25 * 6;
y = 150;
```

Usage of increment operators

1 Answers1