Django, override django.contrib.* models

Asked Feb 04 '16 at 10:44

Active Feb 26 '16 at 11:56

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Is it possible to add a field to a model in django.contrib.* application without monkeypatching it? I need to add a description CharField to django.contrib.auth.models.Permission. How to make it properly?

UPD: I want to show and edit additional field 'description' in default django.contrib.admin detail view for Permission model (/admin/auth/permission/) I know about python class inheritance, but how to make django.contrib.admin use child model?

edited Feb 26 '16 at 11:56

asked Feb 04 '16 at 10:44

svfat

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Subclassing is the way. – LostMyGlasses Feb 04 '16 at 10:45
@LostMyGlasses I know about subclassing in python. Just can't realize how to use it in my case. Can you provide an example? – svfat Feb 04 '16 at 11:02
`class MyPermissionModel(Permission)`, then just define it like its any other model – Sayse Feb 04 '16 at 11:03
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@svfat http://stackoverflow.com/questions/35198113/how-do-i-modify-a-django-model/35198325#35198325 – bakkal Feb 04 '16 at 11:06

Django, override django.contrib.* models

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