You can do this is there is only ONE "Permit" per State. If you have more than one "Permit", then you cannot auto-move through the workflow (there has to be some reason why you would pick one Permit/Trigger over the other). When I say you "cannot", that's not technically, its practically.
Below is an example of auto-moving through the workflow.
using Stateless;
using System;
using System.Runtime.CompilerServices;
namespace MyExample.BAL.WorkFlows
{
public class TelephoneCallWorkFlow
{
private static volatile StateMachine<TelephoneCallStateEnum, TelephoneCallTriggerEnum> SingletonInstance;
public StateMachine<TelephoneCallStateEnum, TelephoneCallTriggerEnum> Instance
{
[MethodImpl(MethodImplOptions.Synchronized)]
get
{
if (SingletonInstance == null)
{
SingletonInstance = new StateMachine<TelephoneCallStateEnum, TelephoneCallTriggerEnum>(TelephoneCallStateEnum.OffHook);
SingletonInstance.Configure(TelephoneCallStateEnum.OffHook)
.Permit(TelephoneCallTriggerEnum.CallDialed, TelephoneCallStateEnum.Ringing);
SingletonInstance.Configure(TelephoneCallStateEnum.Ringing)
//removing so there is only one valid path workflow//.Permit(TelephoneCallTriggerEnum.HungUp, TelephoneCallStateEnum.OffHook)
.Permit(TelephoneCallTriggerEnum.CallConnected, TelephoneCallStateEnum.Connected);
SingletonInstance.Configure(TelephoneCallStateEnum.Connected)
//.OnEntry(t => StartCallTimer())
//.OnExit(t => StopCallTimer())
//removing so there is only one valid path workflow//.Permit(TelephoneCallTriggerEnum.LeftMessage, TelephoneCallStateEnum.OffHook)
//removing so there is only one valid path workflow//.Permit(TelephoneCallTriggerEnum.HungUp, TelephoneCallStateEnum.OffHook)
.Permit(TelephoneCallTriggerEnum.PlacedOnHold, TelephoneCallStateEnum.OnHold)
;
SingletonInstance.Configure(TelephoneCallStateEnum.OnHold)
//removing so there is only one valid path workflow//.SubstateOf(TelephoneCallStateEnum.Connected)
//removing so there is only one valid path workflow//.Permit(TelephoneCallTriggerEnum.TakenOffHold, TelephoneCallStateEnum.Connected)
//removing so there is only one valid path workflow//.Permit(TelephoneCallTriggerEnum.HungUp, TelephoneCallStateEnum.OffHook)
.Permit(TelephoneCallTriggerEnum.PhoneHurledAgainstWall, TelephoneCallStateEnum.PhoneDestroyed)
;
}
return SingletonInstance;
}
}
public void Fire(TelephoneCallTriggerEnum trigger)
{
Console.WriteLine("............[Firing:] {0}", trigger);
this.Instance.Fire(trigger);
}
}
}
public enum TelephoneCallStateEnum
{
OffHook,
Ringing,
Connected,
OnHold,
PhoneDestroyed
}
public enum TelephoneCallTriggerEnum
{
CallDialed,
HungUp,
CallConnected,
LeftMessage,
PlacedOnHold,
TakenOffHold,
PhoneHurledAgainstWall
}
and now the "auto-move" trick.
TelephoneCallWorkFlow tcwf1 = new TelephoneCallWorkFlow();
IEnumerable<TelephoneCallTriggerEnum> myPermittedTriggers = tcwf1.Instance.PermittedTriggers;
while (null != myPermittedTriggers && myPermittedTriggers.Count() > 0)
{
if (myPermittedTriggers.Count() > 1)
{
throw new ArgumentOutOfRangeException("You cannot auto-move the workflow when there's more than one trigger");
}
TelephoneCallTriggerEnum nextTrigger = myPermittedTriggers.FirstOrDefault();
Console.WriteLine("About to call the 'next' trigger: --> {0}", nextTrigger);
tcwf1.Fire(nextTrigger);
Console.WriteLine("CurrentState: --> {0}", tcwf1.Instance.State);
myPermittedTriggers = tcwf1.Instance.PermittedTriggers;
}
You basically get the PermittedTriggers, and get the first-one (and for auto-move to work there should only be one Permitted-Trigger per State).....and then invoke that trigger.
Again, practically (not technically) you would only do this if there was one Permit/Trigger per State. Thus why I have an exception if there is more than 1. You could "get the first" if there were more than 1, it just wouldn't make any sense.