RegEx Find all xml attribute value

Question

I'm trying to extract all attribute values from a large xml file

s = '<some id="Foo" menu="BAAR"></some>'
output = re.findall( '="(.*)"' ,s)
print output

I'm expecting out put

['Foo','BAAR']

However I'm getting

['Foo" menu="BAAR']

Can anyone please help me pointing out what I'm doing wrong ?

don't use regular expressions to parse XML! – Daniel Feb 04 '16 at 17:40 — Daniel, Feb 04 '16 at 17:40
You might find useful using xpath for this – Federico Piazza Feb 04 '16 at 17:43 — Federico Piazza, Feb 04 '16 at 17:43

score -1 · Accepted Answer · answered Feb 04 '16 at 17:41

-1

In regular expression * is greedy, that means, it takes as much as it can. Just use the non-greedy version *?:

s = '<some id="Foo" menu="BAAR"></some>'
output = re.findall( '="(.*?)"' ,s)
print output

answered Feb 04 '16 at 17:41

Daniel

1 Answers1