symbol endl and cout could not be resolved

Question

I have written this code from a book i am reading but my complier warns be that symbol cout and endl could not be resolved. Why is that.

#include <iostream>
#include <float.h>

int main()

{
    cout << "float: " << endl
         << "stevilo decimalnih mest: " << FLT_DIG         << endl
         << "natancnost stevila....: " << FLT_EPSILON      << endl
         << "Najmanjse stevilo.....: " << FLT_MIN          << endl
         << "Najvecje stevilo......: "  << FLT_MAX         << endl
         << "Bitov v mantisi.......: "  << FLT_MANT_DIG    << endl
         << "Najvecji eksponent....: "  << FLT_MAX_10_EXP  << endl
         << "Najmlajsi eksponent...: "  << FLT_MIN_10_EXP  << endl;

    return 0;
}

2 options: Use `std::` in front of `cout` / `endl` (preferred way), or `using namespace std;` before `int main ()`. — Algirdas Preidžius, Feb 05 '16 at 15:20
Your book must be ancient or very bad. What's with that `#include `, anyway?! — Christian Hackl, Feb 05 '16 at 16:10

Garf365 · Answer 1 · 2016-03-29T13:35:00.490

0

cout and endl are scoped. So you have to inform in which namespace there are.

Use

std::cout
std::endl

or badly add just after include

using namespace std;

edited Mar 29 '16 at 13:35

answered Feb 05 '16 at 15:20

Garf365

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score 0 · Answer 2 · answered Feb 05 '16 at 15:22

0

You would have to use namespace:

#include <iostream>
#include <float.h>
using namespace std;

or:

std::cout

You can read more about namespaces in c++ here

answered Feb 05 '16 at 15:22

M G

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I dont like the phrasing "would have to use namespace". There is really no need to do so. Actually there are good reasons not do it (see e.g. [here](http://stackoverflow.com/questions/1452721/why-is-using-namespace-std-considered-bad-practice)). – 463035818_is_not_an_ai Feb 05 '16 at 15:41
@tobi303 "would have to use(...) OR std::" – M G Feb 06 '16 at 21:02

symbol endl and cout could not be resolved

2 Answers2