According to the Python documentation:
The recommended way to create concrete array types is by multiplying
any ctypes data type with a positive integer. Alternatively, you can
subclass this type and define length and type class variables.
Array elements can be read and written using standard subscript and
slice accesses; for slice reads, the resulting object is not itself an
Array.
Example:
>>> from ctypes import *
>>> TenIntegers = c_int * 10
>>> ii = TenIntegers(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
>>> print ii
<c_long_Array_10 object at 0x...>
>>> for i in ii: print i,
...
1 2 3 4 5 6 7 8 9 10
>>>
So, the first part ctypes.c_int * len(x)
creates an array type with len(x)
elements:
In [17]: ctypes.c_int * 10
Out[17]: __main__.c_int_Array_10
In [18]: ctypes.c_int * 100
Out[18]: __main__.c_int_Array_100
After the type creation, you should call it and pass array elements:
(ctypes.c_int * len(x))(*x)
# ^^^^
Created array type accepts variadic number of elements, so, you should expand list x
using the *x
form:
In [24]: x = [1, 2, 3]
In [25]: (ctypes.c_int * len(x))(*x)
Out[25]: <__main__.c_int_Array_3 at 0x7f0b34171ae8>
In [26]: list((ctypes.c_int * len(x))(*x))
Out[26]: [1, 2, 3]
In [27]: (ctypes.c_int * len(x))(*x)[1]
Out[27]: 2
You cannot pass x
, since __init__
expects integers:
In [28]: (ctypes.c_int * len(x))(x)
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-28-ff45cb7481e4> in <module>()
----> 1 (ctypes.c_int * len(x))(x)
TypeError: an integer is required (got type list)