How do I add white space in regex?

Question

I have this code:

CODE JS:

const phone= /^\(?(\d{3})\)?[-]?(\d{3})[-]?(\d{4})$/;

After running this code has the following form

(123)132-1312

I want to add white space before the last parentheses as in the example below.

(123 )132-1312

Can you please tell me how to accept changes to the code so that white space?

Thanks in advance!

EDIT:

text = $(this).val().replace(/(\d{3})(\d{3})(\d{4})/, "($1)$2-$3");
var testt=$(this).val().match(text);

I added this code to call here as add white space ...

I think there must be other questions asking the same thing. — rrk, Feb 08 '16 at 07:55
http://stackoverflow.com/questions/15472764/regular-expression-to-allow-spaces-between-words — cfprabhu, Feb 08 '16 at 07:57
Is the white space before last parenthesis qptional or required ? — ashfaq.p, Feb 08 '16 at 07:57
Question is not clear now. What is the input and what is your expected output? — anubhava, Feb 08 '16 at 09:11

score 1 · Accepted Answer · edited Feb 08 '16 at 09:45

1

This should work as you need:

/^\(?\s*(\d{3})\s*\)?[-]?(\d{3})[-]?(\d{4})$/

edited Feb 08 '16 at 09:45

vard

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answered Feb 08 '16 at 07:59

Ram

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score 1 · Answer 2 · answered Feb 08 '16 at 08:03

1

Depending on wether you always want the whitespace befor the closeing parenthesis or not your could go with:

^$?(\d{3}\s?)$?[-]?(\d{3})[-]?(\d{4})$

Background \s is for whitespaces. the ? stands for 0 or 1 occurrance of the previous sign. if you use + it is one or more and * is for 0 or more occurrences of the previous sign.

To test your regex you can always use regexpal

answered Feb 08 '16 at 08:03

Fuujin

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I edited my post a little ... can you tell me please how do I change now? – Marius Feb 08 '16 at 08:30
try using this: `text = $(this).val().replace(/(\d{3}\s?)(\d{3})(\d{4})/, "($1 )$2-$3");` – Fuujin Feb 08 '16 at 09:58

How do I add white space in regex?

2 Answers2