I am trying to convert the cron expression to date.
for example this is 0 0 23 1 1-12 ?
expression. I want to convert to corresponding date.
How do I achieve this?
This is what I tried but it just give the description, Human readable but I want to achieve proper date format.
import java.text.ParseException;
import java.util.Date;
import org.quartz.CronExpression;
public class CRON {
public static void main(String args[]) throws ParseException
{
//AutoRegistrationJobDao obj=new AutoRegistrationJobDao();
//obj.updateLastAutoRegSchdl();
String cron ="0 0 23 1 1-12 ?";
System.out.println("cron :"+cron);
CronExpression cronExpression =new CronExpression("0 0 23 1 1-12 ?");
System.out.println(cronExpression.getExpressionSummary());
System.out.println(cronExpression.getFinalFireTime());
//System.out.println(cronExpression.getNextValidTimeAfter(date));
try {
CronExpression c =new CronExpression(cron);
Date date=c.getFinalFireTime();
System.out.println(date);
System.out.println(c.getFinalFireTime());
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
seconds: 0
minutes: 0
hours: 23
daysOfMonth: 1
months: 1,2,3,4,5,6,7,8,9,10,11,12
daysOfWeek: ?
lastdayOfWeek: false
nearestWeekday: false
NthDayOfWeek: 0
lastdayOfMonth: false