how to split up an item in a line according to multiple factors (python)

Question

I have a line in a file:

['18G01G03G06G09G11G12G17G19G23G31G32R01']

I need to split it up so that it results in:

['18', 'G01', 'G03', 'G06', 'G09', 'G11', 'G12', 'G17', 'G19', 'G23', 'G31', 'G32', 'R01']

I cant find a way on stackoverflow which explains this although i'm probs wrong. Can anyone help?

Looks like you might be looking for something like this: http://stackoverflow.com/questions/2277352/python-split-a-string-at-uppercase-letters — PtK, Feb 10 '16 at 12:18

Avinash Raj · Answer 1 · 2016-02-10T12:46:31.787

4

You may use re.findall

import re
s = ['18G01G03G06G09G11G12G17G19G23G31G32R01']
re.findall(r'[A-Z]?\d+', s[0])

edited Feb 10 '16 at 12:46

answered Feb 10 '16 at 12:17

Avinash Raj

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Thanks, that seems to work, I hadn't come across re.findall- relatively new to python :) – Theodore Eliot David Harris Feb 10 '16 at 12:26
There's also `R` to split on. – Peter Wood Feb 10 '16 at 12:33
1

Why not `r'[GR]?\d+'`? – Peter Wood Feb 10 '16 at 15:18
@AvinashRaj I am sorry! I missed the `R`! – Pynchia Feb 10 '16 at 17:23

score 0 · Answer 2 · answered Feb 10 '16 at 12:36

Without using regex you could do it logically.

Code:

lst = ['18G01G03G06G09G11G12G17G19G23G31G32R01']
ind =0
count =0
new_lst=[]
for index, val in enumerate(lst[0]):
    if val.isalpha():
        new_lst.append(lst[0][ind:index])
        ind=index

if ind<len(lst[0]):
    new_lst.append(lst[0][ind:])
print new_lst

Output:

['18', 'G01', 'G03', 'G06', 'G09', 'G11', 'G12', 'G17', 'G19', 'G23', 'G31', 'G32', 'R01']

how to split up an item in a line according to multiple factors (python)

2 Answers2