Simple python assignment

Question

basically I need the user to enter an ip address. All I need to do is check that it's valid (0-255; 4 octets). lets say a user enters 192.168.10.1, how can I break it down to 192, 168, 10, 1?

This can be solved via regular expressions. What have you tried so far? — BlackVegetable, Feb 11 '16 at 19:53
This can be solved trivially without regular expressions: `"192.168.0.1".split('.') == ['192', '168', '0', '1']` — Jon Surrell, Feb 11 '16 at 19:57
Check out [How to check if a string matches an IP adress pattern in python?](http://stackoverflow.com/q/3462784) — Bhargav Rao, Feb 11 '16 at 20:01
If your problem is solved, you should accept the answer that helped the most. That gives a reward to the person who helped you and removes this question from the unanswered list. — zondo, Apr 10 '16 at 03:43

zondo · Answer 1 · 2016-02-11T19:57:51.813

3

Do this:

while True:
    ip = raw_input("Please enter an ip address")
    ip_split = ip.split(".")
    if len(ip_split) != 4:
        print "Must have 4 numbers"
    elif not all(number.isdigit() for number in ip_split):
        print "Must be numbers"
    elif not all(0 <= int(number) <= 255 for number in ip_split):
        print "Numbers must be in 0-255 range"
    else:
        ips = [int(number) for number in ip_split]
        break

edited Feb 11 '16 at 19:57

answered Feb 11 '16 at 19:55

zondo

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Wouldn't this allow "999.999.999.999", which is not legal? – Kevin Feb 11 '16 at 19:56
@Kevin: Thank you for mentioning that. I have updated my answer. – zondo Feb 11 '16 at 19:58

Christian Tapia · Answer 2 · 2016-02-11T19:55:41.767

1

You can use the split method:

 your_string.split(separator)

In your case:

 ip = "191.168.10.1"
 values_list = ip.split(".")

edited Feb 11 '16 at 19:55

answered Feb 11 '16 at 19:53

Christian Tapia

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score 0 · Answer 3 · answered Feb 11 '16 at 20:00

0

I have this 2 regexes to check this

import re

ip4 = re.compile(r'^(?:(?:25[0-5]|2[0-4]\d|1\d\d|\d?\d)\.){3}(?:25[0-5]|2[0-4]\d|1\d\d|\d?\d)$')
ip6 = re.compile(r'^(?:[\da-fA-F]{1,4}:){7}[\da-fA-F]{1,4}$')

answered Feb 11 '16 at 20:00

Mr. E

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score 0 · Answer 4 · answered Feb 11 '16 at 20:05

You can do it in several ways. This could be a solution:

ip = "192.168.10.666"
octates = ip.split('.',4)

flag = True
for each_octate in octates:
    num = int(each_octate)
    if num>=0 and num<=255:
        continue
    else:
        flag = False
        break

if flag == True:
    print "IP is correct!"
else:
    print "IP is incorrect"

score 0 · Answer 5 · answered Feb 12 '16 at 02:15

you can take the ip address in as a string and then from there split the str by "." and then check each member for that criteria.

ip = input("Enter Ip address: ")
address = ip.split('.')
if len(address) == 4:
     for num in address:
          if 255 >= num >= 0:
               pass
          else:
               print("Invalid Ip Address!")
else:
     print("Invalid Ip Address!")

Simple python assignment

5 Answers5