R: apply a function to every element of two variables respectively

Question

I have a function with two variables x and y:

fun1 <- function(x,y) {
  z <- x+y
  return(z)
}

The function work fine by itself:

fun1(15,20)

But when I try to use it with two vectors for x and y with an apply function I do not get the correct 56*121 array

Lx  <- c(1:56)
Ly <- c(1:121)

mapply(fun1, Lx, Ly)

I would be grateful for your help and also on advice on the fastest solution (eg is a data.table or dplyr solution faster than apply).

think you want `outer` : `outer(Lx, Ly, fun1)` or [this q/a](http://stackoverflow.com/questions/34858734/sum-of-subvectors-of-a-vector-in-r) — rawr, Feb 12 '16 at 00:25

score 12 · Answer 1 · edited Jun 03 '22 at 18:03

If you want to use mapply() you have to provide it with n lists of arguments that have same size, and that will be passed to the function n by n, as in:

mapply(fun1,c(1,2,3), c(4, 5, 6))
[1] 5 7 9

or one argument can be a scalar as in:

mapply(fun1,c(1,2,3), 4)
[1] 5 6 7

Since you're trying to use all combinations of Lx and Ly, you can iterate one list, then iterate the other, like:

sapply(Lx, function(x) mapply(fun1,x,Ly))

or

sapply(Ly, function(y) mapply(fun1,Lx,y))

which produces same result as rawr's proposition in their comment above

outer(Lx, Ly, fun1)

where outer() is much quicker

score 0 · Answer 2 · answered Feb 16 '16 at 05:03

Using dplyr for this problem, as you've described it, is weird. You seem to want to work with vectors, not data.frames, and dplyr functions expect data.frames in and return data.frames out, i.e. it's inputs and outputs are idempotent. For working with vectors, you should use outer. But dplyr could be shoehorned into doing this task...

# define variables
Lx  <- c(1:56)
Ly <- c(1:121)
dx <- as.data.frame(Lx)
dy <- as.data.frame(Ly)

require(dplyr)
require(magrittr)  # for the %<>% operator

# the dplyr solution
(dx %<>% mutate(dummy_col = 1)) %>% 
     full_join(
         (dy %<>% mutate(dummy_col = 1)), by='dummy_col') %>% 
     select(-dummy_col) %>% 
     transmute(result = Lx + Ly)

score 0 · Answer 3 · edited Jun 11 '16 at 16:15

Well you're using vectors of different length but maybe this will help if I understand correctly. I just made a dumby function with variable i

fun1 <- function(x,y) {
  z <- x+y
  return(z)
}


fun1(15,20)


Lx  <- c(1:56)
Ly <- c(1:121)


fun1I <- function(x,y,i)
{


  fun1(x[i],y[i])


}


fun1IR <- function(x,y)
{


  function(i)fun1I(x=x,y=y,i=i) #return dumby function

}



testfun <- fun1IR(Lx,Ly) # creates function with data Lx and Ly in variable i

mapply(testfun, 1:min(length(Lx),length(Ly)))

R: apply a function to every element of two variables respectively

3 Answers3

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