generating random numbers in visual basics

Question

I am using a random number generator in my program, however it keeps returning the same value (0.71) every time i run the program.

code:

number = FormatNumber(Rnd(1), 2)
    rdmlabelTxt.Text = number.ToString

is there a way to produce a different random number when starting the program? thanks.

Read the docs - https://msdn.microsoft.com/en-us/library/f7s023d2(v=vs.90).aspx — osman, Feb 16 '16 at 23:44
Possible duplicate of [True Random Number Generating](http://stackoverflow.com/questions/19672483/true-random-number-generating) — Blackwood, Feb 16 '16 at 23:57
Possible duplicate of [Call to Rnd() generating the same number](http://stackoverflow.com/questions/34644576/call-to-rnd-generating-the-same-number) — David Wilson, Feb 17 '16 at 01:26

score 1 · Answer 1 · answered Feb 16 '16 at 22:42

According to Microsoft "the same number sequence is generated" when you don't give a parameter. The article also suggests to "Before calling Rnd, use the Randomize statement without an argument to initialize the random-number generator with a seed based on the system timer."

I think this will solve your issue - let us know.

score 0 · Answer 2 · answered May 20 '16 at 21:18

0

You are required to write a for loop to be able to generate different numbers

For i = 1 to 100
number = FormatNumber(Rnd(1), 2)
Cells(i, "A").Value = number
next i

answered May 20 '16 at 21:18

Zapata

133
1
5
20

score 0 · Answer 3 · answered Jun 12 '16 at 11:33

0

You just have to use Randomize() call before your codes.

Randomize()
Dim number As Double = 0
number = FormatNumber(Rnd(1), 2)
rdmlabelTxt.Text = number.ToString

answered Jun 12 '16 at 11:33

Gaurang

67
8

You should make it clearer that `Randomize()` should only be called once in the whole program. But then your answer will be the same as Mark's, so unfortunately you are not adding any value to this post. – Andrew Morton Jun 12 '16 at 12:03

generating random numbers in visual basics

3 Answers3