Nasim, this is one of the most fundamental concepts in C. It should be well-explained in any C book/tutorial you use. That said, everybody needs to learn somewhere. In order to pass values to/from a function, you start with the declaration of a function.
A function in C may receive any number of parameters but may only return a single value (or no value at all). A function requires those parameters specified in its parameter list. A function declaration takes the form of:
type name (parameter list);
The type is the return type for the function (or void
). The parameter list contains the type of variables that are passed to the function. While you will normally see a parameter list in a declaration that contains both the type and name, only the type is required in the declaration. A function definition provides the function code and the function return. The parameter list for a function definition will contain both the type and name of the parameters passed.
(note: you may see old K&R function definitions without any type relying on the fact that the default type is int
. That type definition/parameter list is obsolete. see Function declaration: K&R vs ANSI)
Now that you have had a Cliff's-notes version of how to declare/define a function, a short example should illustrate passing/returning values to and from a function. This first example shows the function definitions that precede the main
function. In this case no separate declaration is required:
#include <stdio.h>
int bar (int x) {
return x + 5;
}
int foo (int a) {
return bar(a);
}
int main (void) {
int n = 5;
printf ("\n n = %d, foo(%d) = %d\n\n", n, n, foo(n));
return 0;
}
(note: function bar
is placed before function foo
because function foo
relies on bar
. A function must always have at minimum a declaration before it is called.)
Another example showing the common use of providing function declarations before main
with the function definitions below would be:
#include <stdio.h>
int foo (int);
int bar (int);
int main (void) {
int n = 5;
printf ("\n n = %d, foo(%d) = %d\n\n", n, n, foo(n));
return 0;
}
int foo (int a) {
return bar(a);
}
int bar (int x) {
return x + 5;
}
(note: even though the function foo
is defined before bar
here, there is no problem. Why? Because bar
is declared (at the top) before foo
is called. also note: the declaration are shown with the type only, just to emphasize a point, you will normally see int foo (int a);
and int bar (int x);
as the declarations.)
Use/Output
The output of both is:
$ ./bin/func_pass_param
n = 5, foo(5) = 10
I hope this has cleared up some of the basics for you. If not, you can ask further, but you are far better served finding a good C book or tutorial and learning the language (at least the basics) before you attempt to compile and run a program -- it will take you far less time in the long run.