Scala - Cannot use a method returning play.api.mvc.Result as a Handler for requests

Question

I have this controller in Scala:

def commonRedirect(anId: Long) = {
implicit val aRule = CommonClient.getTheRule(anId)
aRule match {
  case false ⇒ Redirect("/general-rule/" + anId)
  case true  ⇒ Redirect("/custom-rule/" + anId)
}

}

but, this result in the error: "Cannot use a method returning play.api.mvc.Result as a Handler for requests".

If I apply an Action Builder, it works, but this is not the way that I want.

Any ideas to resolve this?

Thanks.

Can you specify how you want to use `commonRedirect`. I have no errors with your code. — andrey.ladniy, Feb 18 '16 at 15:18

score 14 · Accepted Answer · answered Feb 18 '16 at 15:45

14

You need to make an Action.

def commonRedirect(anId: Long) = Action {
  implicit val aRule = CommonClient.getTheRule(anId)
  aRule match {
    case false ⇒ Redirect("/general-rule/" + anId)
    case true  ⇒ Redirect("/custom-rule/" + anId)
  }
}

answered Feb 18 '16 at 15:45

Paul Draper

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Thanks @paul-draper. I found in http://stackoverflow.com/a/28247637/1665906 that the required type for that is not just `Result` but `⇒ Result`, and that is an Action. – Lucas Feb 19 '16 at 14:18

Scala - Cannot use a method returning play.api.mvc.Result as a Handler for requests

1 Answers1