You can use <IMG>
tag to display images stored in the database by calling another ASP page in SRC attribute of <IMG>
tag.
<IMG SRC="ShowPicture.asp?PhotoId=1">
where PhotoId
is the ID stored in the database.
Following are the steps which needs to be executed:
Create table Users in MS-Access or SQL server.
Create ShowPicture.asp page.
Call this page using <IMG> tag wherever required.
Create table with the following structure:
Table name: Users
user_id (AutoNumber)
user_name (Text)
user_photo (Ole Object - For MS-Access, and Image data type for SQL server).
Code
ShowPicture.asp is used to display images. You need to pass user ID in querystring, and for that user ID, image will be displayed. Following is the code:
'Declare Variables..
Dim sql
Dim rs
Dim conn
Dim userID,str
userID = Request("PhotoId")
If userID = "" Then userID = 0
'Instantiate Objects
Set conn = Server.CreateObject("ADODB.Connection")
Set rs = Server.CreateObject("ADODB.Recordset")
'Open connection
Conn.Open "Provider=Microsoft.Jet.OLEDB.4.0;" & _
"Data Source=" & Server.MapPath("data.mdb")
'Get the specific image based on the ID passed in a querystring
str = "SELECT user_photo FROM users where user_id =" & userID
rs.Open str, conn,3,3
if rs.eof then 'No records found
Response.End
else 'Display the contents
Response.ContentType = "image/gif"
Response.BinaryWrite(rs("user_photo"))
end if
'destroy the variables.
rs.Close
conn.Close
set rs = Nothing
set conn = Nothing
Please note that "Response.contentType"
will depend on the type of content you would like to display. For example, to display jpg image, following will be the code:
Response.ContentType = "image/jpg"
To use above page for displaying images, following is the example:
<IMG SRC="ShowPicture.asp?PhotoId=1">
<IMG SRC="ShowPicture.asp?PhotoId=2">
Upload Image
Following example shows how to upload images in database by using ASPSmartUpload component.
Following is the code to upload image:
<FORM METHOD="POST" ACTION="saveFile.asp"
ENCTYPE="multipart/form-data" NAME="UploadForm">
<center>
Employee Name : <INPUT TYPE="TEXT" NAME="USERNAME" SIZE="30"><br>
<INPUT TYPE="FILE" NAME="UPLOADFILE1" SIZE="50">
</center>
<BR>
<center><INPUT TYPE="SUBMIT" VALUE="Upload"
id=SUBMIT1 name=SUBMIT1></center>
</FORM>
Code to save the image in the database:
Dim myupload
'declare variables..
intCount=0
' Create Upload Component
Set myupload = Server.CreateObject("aspSmartUpload.SmartUpload")
myupload.Upload
'Create Connection
Set Conn = Server.CreateObject("ADODB.Connection")
Conn.Open "Provider=Microsoft.Jet.OLEDB.4.0;" & _
"Data Source=" & Server.MapPath("data.mdb")
Set Rs = Server.CreateObject("ADODB.recordset")
Rs.Open "SELECT user_id,user_name,user_photo FROM users", Conn,3,3
'Select each file
For each file In myupload.Files
If not file.IsMissing Then 'Check for missing file
'Add the current file in database
Rs.AddNew
file.FileToField Rs.Fields("user_photo")
Rs("user_name") = myupload.Form("USERNAME")
Rs.Update
intCount = intCount + 1
End If
Next
Response.Write(intCount & " file(s) uploaded.")
'Destroy the objects...