Swift NSURL error while creating

Question

This is my code. Error: fatal error: unexpectedly found nil while unwrapping an Optional value (lldb) I have no idea where;s the problem

res = "https://www.example.com/range.php?arr1=48.15&arr2=48.15&API_KEY=>code"
    let url = NSURL(string: res)! // error line
    print("url craeted" + res)
    return url

`>` is not a valid character for an URL. Encode your URL: http://stackoverflow.com/q/24551816/2227743, http://stackoverflow.com/a/30149081/2227743, etc — Eric Aya, Feb 19 '16 at 15:21

score 0 · Answer 1 · answered Feb 19 '16 at 16:09

You can use an extension to encode your URL

extension String {
    func urlEncodedString() -> String {
        let urlEncodedString = self.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())
        return urlEncodedString ?? self
    }
}

score 0 · Accepted Answer · answered Feb 19 '16 at 16:19

0

The combination => leads to an instruction failure and let's the string not be interpreted as a string. By the way, I assume res has been defined somewhere else in your code and you want to change "url created" into "url created", later.

answered Feb 19 '16 at 16:19

MacUserT

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Swift NSURL error while creating

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