I am still knew in learning c and i am facing the following problem.
I am trying to initialize and declare an array but it is giving me compilation error.
const int a =2;
int x[a]={2};
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use macro to define the constant size. – Jason Hu Feb 21 '16 at 17:07
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Please **always** mention the exact error you get. – Spikatrix Feb 21 '16 at 17:12
2 Answers
5
Variable length arrays cannot be initialized.
Assign the values after definition:
const int a = 2;
int x[a];
x[0] = 2;
2501
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@adminXVII No, `a` is not a constant, it is merely defined with const. `x` is a variable length array. Please read: https://stackoverflow.com/questions/3025050/error-initializer-element-is-not-constant-when-trying-to-initialize-variable-w, and https://stackoverflow.com/questions/12343027/const-keyword-and-constant-expressions-in-c99-and-c11, and C11 6.6 Constant expressions, and 6.2.5.Types paragraph 23 – 2501 Feb 22 '16 at 08:03
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1
By using macro you can do that
#include<stdio.h>
#define a 2
int main()
{
int x[a]={2};
//do something with array x
return 0;
}