How to prompt user for a number until they choose an Odd number? C++

Question

int main() {
    int num;
    cout << "Enter a number: ";
    cin >> num;
    cout << "you entered ";
    cout << num;
    cout << endl;
    return 0;
}

How will a program know when an odd number is input by the user?

For an "If statement"... I can't say If (num == odd) { cout << "all done"

Possible duplicate of [How do I check if an integer is even or odd?](http://stackoverflow.com/questions/160930/how-do-i-check-if-an-integer-is-even-or-odd) — mech, Feb 22 '16 at 05:31
You'll need to look at loops. Do-while loop is probably what you're looking for. Do "prompt" while "num % 2 != 0" — M.Alnashmi, Feb 22 '16 at 05:34

score 1 · Accepted Answer · answered Feb 22 '16 at 05:39

1

By using the Modulus Operator, you can detect whether a number is even or odd. You can think of the modulus operator (%) as giving you the 'remainder' after a division. For example, 12 % 2 would give you 0. 13 % 2 would give you 1. In this way, just do

if (variable % 2 == 1)

to check if your variable is odd.

answered Feb 22 '16 at 05:39

Ethan Fischer

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Played around with this idea for about an hour and ended up getting it. Thank you.. – timwheelz Feb 22 '16 at 07:06
You're welcome! Do you mind upvoting or accepting my answer? Trying to raise my score :) – Ethan Fischer Feb 22 '16 at 07:09
1

Yes sir! won't let me up vote because I am too new to the site but I accepted answer. thanks again. – timwheelz Feb 22 '16 at 07:19

How to prompt user for a number until they choose an Odd number? C++

1 Answers1