URL encode parameters

Question

Was wondering how to url encode my parameters, is this right?

 params = {'oauth_version': "1.0", 
              'oauth_nonce': oauth.generate_nonce(), 
              'oauth_timestamp': int(time.time()),
              'oauth_consumer_key': CONSUMER_KEY,
              'oauth_token': access_key,
              'oauth_nonce' : nonce, 
              'oauth_consumer_key': consumer.key,
              'oauth_signature': 'el078a5AXGi43FBDyfg5yWY',
              }

Following this guide:

To make the Authorization header, you simply append all the values starting with “OAuth”. Each value must be URL encoded.

> 1. Authorization: OAuth oauth_callback="http%3A%2F%2Fwww.website-tm-access.co.nz%2Ftrademe-callback",
> oauth_consumer_key="C74CD73FDBE37D29BDD21BAB54BC70E422",
> oauth_version="1.0", oauth_timestamp="1285532322",
> oauth_nonce="7O3kEe", oauth_signature_method="HMAC-SHA1",
> oauth_signature="5s3%2Bel078a5AXGi43FBDyfg5yWY%3D"

Possible duplicate of [How to percent-encode url parameters in python?](http://stackoverflow.com/questions/1695183/how-to-percent-encode-url-parameters-in-python) — Flavian Hautbois, Feb 22 '16 at 21:28
I see parameters, but I don't see how you're URL-encoding them. — jwodder, Feb 22 '16 at 21:29

Flavian Hautbois · Answer 1 · 2016-02-24T12:03:09.190

0

You should use urllib.quote_plus or urllib.parse.quote_plus in python 3, which will handle it nicely for you.

The way you want to construct your authorization header from your params is the following:

(python3 version)

import urllib
authorization = 'OAuth ' + ', '.join([key + '="' + urllib.parse.quote_plus(str(value)) + '"' for key, value in params.items()])
http_headers = {'Authorization': authorization}

(python2 version)

import urllib
authorization = 'OAuth ' + ', '.join([key + '="' + urllib.quote_plus(str(value)) + '"' for key, value in params.items()])
http_headers = {'Authorization': authorization}

However, you may want to have a look at existing implementations, such as requests-oauth1. See here.

edited Feb 24 '16 at 12:03

answered Feb 22 '16 at 21:35

Flavian Hautbois

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Hi, I get TypeError: quote_from_bytes() expected bytes – musss Feb 23 '16 at 00:35
1

Try to make sure all values in the params dict are cast to strings – Flavian Hautbois Feb 23 '16 at 10:05
Should I try a for statement and convert i in list to str(i) ? – musss Feb 23 '16 at 18:39
I added a cast to string in my code, could you try it? – Flavian Hautbois Feb 24 '16 at 12:03

URL encode parameters

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