Count number of words in a string of length less than n

Question

int wordcount(char *str,int n)
  {
    int i=0,count=0,count1=0;

    for(i=0;i<strlen(str);i++)
      {
        if(str[i]!=' ' || str[i]!='\n' || str[i]!='\t')
         {
           count++;
         }

    else
    {
        if(count<=n)
        {
            count1++;
        }
    count=0;
    }


}
if(count<=n)
return (count1+1);
else
return count1;
}

count the number of words in str with number of characters equal to or less than length. The word must have whitespace on both sides (space, tab, newline or carriage return), unless it is at the beginning or end of the string str . For example if length == 3 , the function should be able to count all occurrences of words such as {the, in, a, of, all, ...etc}

My problem is: Whenever I enter the '\n' and '\t' and '\r' in the if statement with an or condition alongside ' ' it is giving 0 as answer but if I am only using ' ' it gives me correct answer.

Can anybody explain it to me?

Please show, as opposed to describing, the code you are asking about. — Scott Hunter, Feb 23 '16 at 01:19
Rewrite that while loop into a for loop, and you'll see what's happening. — lost_in_the_source, Feb 23 '16 at 01:23
Since you tagged this as C++, usage of `std::istringstream` makes this very simple. — PaulMcKenzie, Feb 23 '16 at 01:31

score 1 · Accepted Answer · answered Feb 23 '16 at 01:18

1

Because you used i++ in the loop guard, the character you are testing inside the loop is the one after the one you just made sure wasn't the null terminating the string.

answered Feb 23 '16 at 01:18

Scott Hunter

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I got that but my main problem is still checking for tab and next line character and it is giving me wrong value as soon as I am adding these two characters with an or condition in the if loop. – Max Feb 23 '16 at 01:42

Count number of words in a string of length less than n

1 Answers1