I understand this is an old question, but I needed this exact method and I wrote it up like so:
public static int ContainsSubsequence<T>(this IEnumerable<T> elements, IEnumerable<T> subSequence) where T: IEquatable<T>
{
return ContainsSubsequence(elements, 0, subSequence);
}
private static int ContainsSubsequence<T>(IEnumerable<T> elements, int index, IEnumerable<T> subSequence) where T: IEquatable<T>
{
// Do we have any elements left?
bool elementsLeft = elements.Any();
// Do we have any of the sub-sequence left?
bool sequenceLeft = subSequence.Any();
// No elements but sub-sequence not fully matched
if (!elementsLeft && sequenceLeft)
return -1; // Nope, didn't match
// No elements of sub-sequence, which means even if there are
// more elements, we matched the sub-sequence fully
if (!sequenceLeft)
return index - subSequence.Count(); // Matched!
// If we didn't reach a terminal condition,
// check the first element of the sub-sequence against the first element
if (subSequence.First().Equals(e.First()))
// Yes, it matched - move onto the next. Consume (skip) one element in each
return ContainsSubsequence(elements.Skip(1), index + 1 subSequence.Skip(1));
else
// No, it didn't match. Try the next element, without consuming an element
// from the sub-sequence
return ContainsSubsequence(elements.Skip(1), index + 1, subSequence);
}
Updated to not just return if the sub-sequence matched, but where it started in the original sequence.
This is an extension method on IEnumerable, fully lazy, terminates early and is far more linq-ified than the currently up-voted answer. Bewarned, however (as @wai-ha-lee points out) it is recursive and creates a lot of enumerators. Use it where applicable (performance/memory). This was fine for my needs, but YMMV.