How to get a string after keyword

Question

I would like to get the string after a specific keyword.

For example:

import re
def findWholeWord(w):
return re.compile(r'\b({0})\b'.format(w), flags=re.IGNORECASE).search

abc = "<StephenCurry Pro='ThreepointShooter'>MVP1times</StephenCurry>"
if findWholeWord("SeedNumber")(abc):
    dddd = re.search('(?<=ThreepointShooter)(.\w+)', abc)
    mvp = dddd.gorup()
    print (mvp)

    print ("found")
else:
    print ("not found")

I expect the result suppose to be 'MVP1times'.

Is there any better method to find a specific string after keyword ? the result maybe a string, Digit or even mix like the result above.

Thanks for help!

[Why don't you use XML parser?](http://stackoverflow.com/q/1732348/38218040) — GingerPlusPlus, Feb 29 '16 at 09:21
Because I want to try it in another way..thx for ur suggestion also, i have tried the XML — Dsw Wds, Mar 02 '16 at 09:36

score 1 · Accepted Answer · answered Feb 29 '16 at 09:04

1

You can use look-arounds to get the string surrounded by > and < (assuming this stays consistent):

>>> s = "<StephenCurry Pro='ThreepointShooter'>MVP1times</StephenCurry>"

>>> re.search(r'(?<=\>)[^<]+(?=\<)', s).group(0)
'MVP1times'

answered Feb 29 '16 at 09:04

heemayl

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score 0 · Answer 2 · answered Feb 29 '16 at 08:45

0

You can change the regular expressiion to: (?<=ThreepointShooter['|"]>)(.\w+). See it live on http://pythex.org/

I'm not sure what exactly your going to do but you don't even need to use lookbehind expression here.

answered Feb 29 '16 at 08:45

martin

93,354
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Thx ! i will try and see – Dsw Wds Feb 29 '16 at 08:52
dddd = re.search("""?<=ThreepointShooter['|"]>)(.\w+)""" , abc) how do i avoid the quotation mark? I get none attribute in dddd for this case – Dsw Wds Feb 29 '16 at 09:11
originally my coding is: dddd = re.search('(?<=ThreepointShooter)(.\w+)', abc) and your coding (?<=ThreepointShooter['|"]>)(.\w+) inside got one apostrophe.. so how do i avoid it? – Dsw Wds Mar 01 '16 at 01:13

How to get a string after keyword

2 Answers2