Parse whitespaces from String value to HTTP url standard

Question

How can I get a parse String of city name without whitespaces (on the start and at the end) and with "%20" instead of " " (which contains some city names) in android.

For example I would like to parse:

" Oklahoma " -> "Oklahoma"

or

"    Oklahoma    City" -> "Oklahoma%20City"

Possible duplicate of [Java how to replace 2 or more spaces with single space in string and delete leading spaces only](http://stackoverflow.com/questions/2932392/java-how-to-replace-2-or-more-spaces-with-single-space-in-string-and-delete-lead) — Selvin, Feb 29 '16 at 16:47

score 1 · Accepted Answer · answered Feb 29 '16 at 16:29

1

Uri.encode(" Oklahoma  City".trim())

Output :

Oklahoma%20%City

answered Feb 29 '16 at 16:29

Leonid Veremchuk

1,952
15
27

"Oklahoma [space][space]City" Output: `Oklahoma%20%20City` ... should be `" Oklahoma City".replaceAll("\\s+", " ").trim()` – Selvin Feb 29 '16 at 16:46
For me Leonid's code works fine. I get from geocode API what I need! But thanks you too. – y07k2 Feb 29 '16 at 17:05

Parse whitespaces from String value to HTTP url standard

1 Answers1