How to get asterisk value from BASH input

Question

Following is the input from command line:

bash script.sh "input*" ";" "21" "yyyy-MM-dd"

and in my current directory i have two input files:

While i want to get value 'input*' from input '$1' i got 'input1.txt input2.txt' as input.

Is there any way to get value 'input*' from '$1'?

ClaudioM · Answer 1 · 2016-03-02T11:16:00.577

-1

you can use "$1" where 1 is the number of first input parameter

#!/bin/bash

echo "$1"

but you have to pass the input*.txt like this input\*.txt

output

[shell] ➤ ./test7.sh input\*.txt
input*.txt

Regards

Claudio

edited Mar 02 '16 at 11:16

answered Mar 02 '16 at 11:03

ClaudioM

The quoting, not the braces, are the beef here. – tripleee Mar 02 '16 at 11:08
@tripleee, what do you mean? – ClaudioM Mar 02 '16 at 11:12
1

Your answer reads as if the braces were important, but they are completely superfluous here. – tripleee Mar 02 '16 at 11:13
you read it in that way.. I didn't wrote that the braces are most important then quoting.. – ClaudioM Mar 02 '16 at 11:15
Partly that, partly because of other issues (the backslash vs quoting discussion is similarly misdirected), partly because this is a FAQ and so it should simply be closed as duplicate, instead of answered. – tripleee Mar 02 '16 at 11:18
I don't have the close permission .. btw have a nice a day – ClaudioM Mar 02 '16 at 11:32

1 Answers1