escape brace expansion with echo

Asked Mar 03 '16 at 14:26

Active Mar 03 '16 at 15:52

Viewed 30 times

I can't make this line to work on my bash script:

echo "VAR=$(ps ax | grep myprocess)" >> myprocess

How should I do to escape the $(ps ax | grep myprocess) expansion?

I want as a result, a myprocess file with this content:

VAR=$(ps ax | grep myprocess)

EDIT: The example I used is too simple, but it was intended to show the specific problem. Here is the real command:

su - -c "echo \"#!/bin/bash\nPID=$(ps ax | grep elasticsearch-${VERSION}.jar | grep -v grep | cut -f1 --delimiter=\" \" -s)\nif [ -n \"\${PID}\" ];\nthen\n\tkill \${PID}\n\techo \"ElasticSearch process killed.\"\nelse\n\techo \"ElasticSearch is not running.\"\nfi\" >> /home/user/start_elastic" user

Some considerations:

I can't change to single quotes, because ${VERSION} would not be replaced.
I tried adding a backslash like this: \$(, but it didn't worked. the evaluation is executed before creating the start_elastic file.

edited Mar 03 '16 at 15:52

asked Mar 03 '16 at 14:26

Facundo Chambo

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Simply put it inside single quotes. – sat Mar 03 '16 at 14:28
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or escape the `$` with a backslash – 123 Mar 03 '16 at 14:32
I added more info on why those options are not possible. – Facundo Chambo Mar 03 '16 at 15:53
Is `$VERSION` the only variable you want evaluated immediately (and both instances of `$PID` plus the command substitution should be deferred)? – Dennis Williamson Mar 16 '16 at 23:57

escape brace expansion with echo

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