start node app from python script

Question

Is it possible to start a node.js app from within a python script on a raspberry pi?

On the command line I run sudo node myscript.js

could I use a library like os?

I don't know about pi but see https://docs.python.org/2/library/subprocess.html#module-subprocess — Selcuk, Mar 04 '16 at 05:36

score 16 · Accepted Answer · edited Apr 13 '17 at 12:56

16

The first line of file shall be:

#!/usr/bin/python

You can call command with subprocess.call:

from subprocess import call

# Note that you have to specify path to script
call(["node", "path_to_script.js"])

Then you have to set +x permissions for file to be executable:

chmod +x filename.py

Know you are ready to go:

./filename.py

Note: checkout Raspberry Pi Stack Exchange, you can find a lot of use full info there.

edited Apr 13 '17 at 12:56

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answered Mar 04 '16 at 06:02

Andriy Ivaneyko

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How can I get the output from the command in my python script? – arshbot Sep 24 '18 at 15:57
1

Figured it out. use `p = subprocess.check_output(["command", "args"])` instead and decode the output with `p.decode("utf-8") ` – arshbot Sep 24 '18 at 16:07

ngoue · Answer 2 · 2016-03-04T05:55:18.640

As Selcuk mentioned in his comment, use the subprocess module:

#! /usr/bin/env python
import subprocess

subprocess.call('sudo node myscript.js')

It's very likely that you'll encounter a FileNotFoundError when trying to run your command with sudo. If you do, you can try:

#! /usr/bin/env python
import subprocess

subprocess.call('sudo node myscript.js', shell=True)

Per the Python documentation, be VERY careful about using the shell=True parameter as this could be a problem if you allow any arbitrary user input to be passed to subprocess.call().

start node app from python script

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