curl command equivalent in java

Question

Here is my curl command:

curl https://login.xyz.com/v1/oauth/token -H "Accept:
application/json" --data 'client_id=client_id' --data
'client_secret=client_secret' --data 'redirect_uri=redirect_uri'
--data 'code=code'

I'm trying to post that in java. Here is what i was trying to do:

String resourceUrl = "https://login.xyz.com/v1/oauth/token?client_id=<client.id>&client_secret=<client.secret>&redirect_uri=https://login.xyz.com/user/login&code=<code>";
HttpURLConnection httpcon = (HttpURLConnection) ((new URL(resourceUrl).openConnection()));
httpcon.setDoOutput(true);
httpcon.setRequestProperty("Content-Type", "application/json");
httpcon.setRequestProperty("Accept", "application/json");
httpcon.setRequestMethod("POST");
httpcon.connect();      
System.out.println(httpcon.getHeaderField(0));

But I'm getting HTTP/1.1 500 Internal Server Error

score 1 · Answer 1 · edited May 23 '17 at 12:09

1

I didn't test but just by looking at the documentation and your source code, I can see some differences between your curl command and the Java implementation:

Curl:

Performs a POST
Content-Type is application/x-www-form-urlencoded

Curl manpage:

-d, --data

(HTTP) Sends the specified data in a POST request to the HTTP server, in the same way that a browser does when a user has filled in an HTML form and presses the submit button. This will cause curl to pass the data to the server using the content-type application/x-www-form-urlencoded. Compare to -F, --form.

See also: How are parameters sent in an HTTP POST request?

Java implementation:

Performs a POST but URL is GET-alike (you set the request method to POST but you're passing the parameters in the URL query string)
Content-Type is application/json

I hope this helps.

edited May 23 '17 at 12:09

Community

1
1

answered Mar 04 '16 at 09:38

Baderous

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1

for POST required: `-X/--request `, -d - just a key for specify data values – Eugene Lebedev Mar 04 '16 at 09:55
1

Not sure if I agree: http://superuser.com/questions/149329/what-is-the-curl-command-line-syntax-to-do-a-post-request – Baderous Mar 04 '16 at 10:27
it seems you right, ```-X``` just for situations when you want to send POST without any data – Eugene Lebedev Mar 04 '16 at 10:31

score 1 · Answer 2 · edited May 11 '20 at 19:23

public class CURLTest {
    public void main(String[] args) throws IOException {
        sendData();
    }

    public String sendData() throws IOException {
        // curl_init and url


        URL url = new URL( "Put the Request here");
        HttpURLConnection con = (HttpURLConnection) url.openConnection();

        // CURLOPT_POST
        con.setRequestMethod("POST");

        // CURLOPT_FOLLOWLOCATION
        con.setInstanceFollowRedirects(true);

        String postData = "my_data_for_posting";
        con.setRequestProperty("Content-length",
            String.valueOf(postData.length()));

        con.setDoOutput(true);
        con.setDoInput(true);

        DataOutputStream output = new DataOutputStream(con.getOutputStream());
        output.writeBytes(postData);
        output.close();

        // "Post data send ... waiting for reply");
        int code = con.getResponseCode(); // 200 = HTTP_OK
        System.out.println("Response    (Code):" + code);
        System.out.println("Response (Message):" + con.getResponseMessage());

        // read the response
        DataInputStream input = new DataInputStream(con.getInputStream());
        int c;
        StringBuilder resultBuf = new StringBuilder();
        while ((c = input.read()) != -1) {
            resultBuf.append((char) c);
        }
        input.close();

        return resultBuf.toString();
    }
}

Here is an example how I would do it

curl command equivalent in java

2 Answers2