I'm using RabbitMQ Bundle for the Symfony2 web framework. My question is, how can I avoid creating multiple connections (to prevent overloading the broker) after running many workers in terminal? In example below, I've run two workers and ended up having two connections/channel.
config.yml
old_sound_rabbit_mq:
connections:
default:
host: 127.0.0.1
port: 5672
user: guest
password: guest
vhost: /
lazy: true
producers:
order_create_bmw:
connection: default
exchange_options: { name: order_create_ex, type: direct }
queue_options:
name: order_create_bmw_qu
routing_keys:
- bmw
consumers:
order_create_bmw:
connection: default
exchange_options: { name: order_create_ex, type: direct }
queue_options:
name: order_create_bmw_qu
routing_keys:
- bmw
callback: application_frontend.consumer.order_create_bmw
services.yml
services:
application_frontend.producer.order_create_bmw:
class: Application\FrontendBundle\Producer\OrderCreateBmwProducer
arguments:
- @old_sound_rabbit_mq.order_create_bmw_producer
Producer
namespace Application\FrontendBundle\Producer;
use Application\FrontendBundle\Entity\Order;
use OldSound\RabbitMqBundle\RabbitMq\ProducerInterface;
class OrderCreateBmwProducer
{
private $producer;
public function __construct(ProducerInterface $producer)
{
$this->producer = $producer;
}
public function add(Order $order)
{
$message = [
'order_id' => $order->getId(),
'car_model' => $order->getCarModel(),
'timestamp' => date('Y-m-d H:i:s')
];
$this->producer->publish(json_encode($message), 'bmw');
}
}
Running workers
$ app/console rabbitmq:consumer order_create_bmw
$ app/console rabbitmq:consumer order_create_bmw
RabbitMQ Management