Selenium wait until one of the two elements is present

Question

A lot of times I want the webdriver to wait for presence of one of the two elements. Normally this happens when I am expecting the page to be showing either element1 in some cases or element 2. Currently I am doing this sequentially using two waits, but it's inefficient since I need to wait 2 times. Is there any way to combine the two waits into one? In other words I want to wait until element1 or element2 is present.

try: 
  element = WebDriverWait(self.browser, 15).until(EC.presence_of_element_located((By.ID, "elem1")))
  element.click()
  return "elem1"
except: 
  print "failed to find elem1"

try: 
  element = WebDriverWait(self.browser, 5).until(EC.presence_of_element_located((By.ID, "elem2")))  
  return "elem2"    
except:
  print "sth wrong!"
  raise  Exception("Sth Wrong!") 

return "Should not get here"

score 26 · Answer 1 · edited Nov 02 '18 at 11:46

26

You can do an OR

driverWait.until(ExpectedConditions.or(
    ExpectedConditions.presenceOfElementLocated(By.cssSelector("div.something")),
    ExpectedConditions.presenceOfElementLocated(By.cssSelector("div.anything"))));

edited Nov 02 '18 at 11:46

undetected Selenium

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answered Apr 16 '18 at 19:48

test automation Red leader

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4

tried it, gave me a syntax error at `or`, is it possible that there's no `or` method – Dariopnc Dec 27 '21 at 09:16
1

I had the same issue as @Dariopnc and this helped me https://stackoverflow.com/questions/16462177/selenium-expected-conditions-possible-to-use-or – Neox Apr 11 '22 at 06:34
Please note that this syntax has been released in selenium 4 – Dariopnc Apr 12 '22 at 07:29
Use `ExpectedConditions.any_of(...)` or `ExpectedConditions.all_of(...)` instead `.or` – allofmex Aug 01 '23 at 16:21

score 13 · Answer 2 · answered Mar 05 '16 at 10:48

13

Not tested, but you can try something like

element = WebDriverWait(self.browser, 15).until(EC.presence_of_element_located((By.CSS_SELECTOR, "#elem1, #elem2")))

The comma in the selector is OR.

answered Mar 05 '16 at 10:48

Guy

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This is the right answer! It's so simple and it works. – David DiGioia Apr 24 '20 at 00:17

score 12 · Answer 3 · answered May 08 '17 at 01:37

12

You could use a lambda

WebDriverWait(driver,15).until(
    lambda driver: driver.find_elements(By.ID,"Id1") or driver.find_elements(By.ID,"Id2"))

answered May 08 '17 at 01:37

Maeda

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Be careful if you ALSO use implicitly_wait(n). Each of the lambdas will take n secs before they return. So, if you had called implicitly_wait(15) and then tried WebDriverWait(driver,15).until(), then only the first lambda would be checked. – SoloPilot Nov 02 '19 at 13:40

score 2 · Answer 4 · answered Oct 11 '22 at 02:29

You can use the any_of method which is implemented inside the ExpectedConditionssection to check if any of the elements are available and this is relevant to the logical expression - "OR".

Example:

from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By

WebDriverWait(driver, 40).until(EC.any_of(
        EC.visibility_of_element_located((By.ID, 'elem1')),
        EC.visibility_of_element_located((By.ID, 'elem2'))
    )
)

BachT · Answer 5 · 2021-11-28T23:01:47.427

This is an alternative solution while I was having problems with other solutions.

For example, if we only have 2 conditions, and 1st is never satisfied while the 2nd is already satisfied. Then the other solutions block until the end of wait_delay before return the result; while the following solution skip it:

WebDriverWait(driver, wait_delay).until(
  wait_for_any([
    EC.presence_of_element_located(locator)
    for locator in locators
]))

where

class wait_for_any:
    def __init__(self, methods):
        self.methods = methods

    def __call__(self, driver):
        for method in self.methods:
            try:
                if method(driver):
                    return True
            except Exception:
                pass
            
        return False

Selenium wait until one of the two elements is present

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