how to get Soap Envelope attribute value in wcf service

Question

How do I get the SOAP xml attribute value in a wcf service?

  <ns3:NotifRQ Status="Commit" 
               xmlns:ns2="http://www.dddd.com/df/dd/" 
               xmlns:ns3="http://www.dd.org/OTA/">

      <ns3:rev>dfdfkkl</ns3:rev>
      <ns3:change>dfdfkkl</ns3:change>
  </ns3:NotifRQ>

This is the code I have now for the data contract:

[DataContract(Name = "NotifRQ", Namespace = "http://www.dd.org/OTA/")]
public class NotifRQ
{
    [DataMember(Name = "Status")]
    public string ResStatus;
}

can you explain briefly ? what you want to get? or what are you truing to say? — Faraz Ahmed, Mar 05 '16 at 12:02
i need to get above SOAP XML () attribute 'Status' value in wcf — Mari, Mar 05 '16 at 12:05

score 0 · Answer 1 · edited May 23 '17 at 12:23

Your Status attribute needs to be a field or property of the NotifRQ class and you need to instruct WCF to use the less optimal XmlSerializer instead of the DatacontractSerializer as explained here. You achieve that by using the XmlSerializerFormat attribute on your class.

You can now apply XmlAttribute to a field or property of your class that gets or sets the value of an attribute on the xml element.

Create and annotate your class as follows:

[DataContract(Namespace="http://www.dd.org/OTA/")]
[XmlSerializerFormat]
public class NotifRQ 
{

   [DataMember, XmlAttribute] 
   public string Status="Commit";

   [DataMember]
   public string  rev;

   [DataMember]
   public string  change;
}

Above class will write and read the following wire-format:

<?xml version="1.0" encoding="utf-16"?>
<NotifRQ xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
         xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
         Status="Commit">
  <rev>foo</rev>
</NotifRQ>

how to get Soap Envelope attribute value in wcf service

1 Answers1