match all except some word

Question

i'm looking for a way, to match all except the some word.

please tell me how i must wrote it?

when i wrote

$str = "i am a programmer";
$word = "am";
preg_match_all("/[^($word)]/", $str, $matched);// it do the same, if i when i wrote
preg_match_all("/[^$word]/", $str, $matched);

i also tried preg_match_all("/[^{$word}]/", $str, $matched); but it doesn't do the job.

how can i tell all except that word ?

Thanks Much

Similar to: http://stackoverflow.com/questions/242698/regex-to-match-all-words-except-a-given-list — Chris Shouts, Aug 27 '10 at 14:17
What do you want the results to be? An array of letters or a string without the word? — Peter Ajtai, Aug 27 '10 at 17:53

score 1 · Answer 1 · answered Aug 27 '10 at 14:02

1

Can't you simply remove all occurrences of the word?

str_replace($word, '', $str);

Or split using explode() or preg_split()? This will give you an array with all parts separated by the word.

answered Aug 27 '10 at 14:02

Sjoerd

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i need it to use it in big regex then, so i exactly need to write something like `[^...]` becouse i need to mention `not that word` too. – Simon Aug 27 '10 at 14:03
Maybe you want to lookaround: http://www.regular-expressions.info/lookaround.html – Sjoerd Aug 27 '10 at 14:04

match all except some word

1 Answers1